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[Bug fortran/82934] New: Segfault on assumed character length in allocate
- From: "pault at gcc dot gnu.org" <gcc-bugzilla at gcc dot gnu dot org>
- To: gcc-bugs at gcc dot gnu dot org
- Date: Fri, 10 Nov 2017 09:40:35 +0000
- Subject: [Bug fortran/82934] New: Segfault on assumed character length in allocate
- Auto-submitted: auto-generated
https://gcc.gnu.org/bugzilla/show_bug.cgi?id=82934
Bug ID: 82934
Summary: Segfault on assumed character length in allocate
Product: gcc
Version: 8.0
Status: UNCONFIRMED
Severity: normal
Priority: P3
Component: fortran
Assignee: unassigned at gcc dot gnu.org
Reporter: pault at gcc dot gnu.org
Target Milestone: ---
Reported by FortranFan on clf:
https://groups.google.com/forum/#!topic/comp.lang.fortran/Lg8tBwlkS6A
character(len=42), allocatable :: foo
call alloc( foo )
print *, "len(foo) = ", len(foo), "; expected = 42"
contains
subroutine alloc( bar )
character(len=*), allocatable :: bar
allocate( character(len=*) :: bar )
end subroutine
end
[pault@pc30 pr78990]$ gfortran -static-libgfortran f*.f90 -O2
fortranfan1.f90:15:0:
allocate( character(len=*) :: bar , barbar)
1
internal compiler error: in gfc_trans_allocate, at fortran/trans-stmt.c:5316
GNU Fortran (GCC) 5.1.1 20150618 (Red Hat 5.1.1-4)
Goes through all the way to trunk.
Paul