[Bug c/80076] New: -Wmisleading-indentation doesn't trigger when macro is misindented

["andres at anarazel dot de" <gcc-bugzilla at gcc dot gnu dot org>]

https://gcc.gnu.org/bugzilla/show_bug.cgi?id=80076

            Bug ID: 80076
           Summary: -Wmisleading-indentation doesn't trigger when macro is
                    misindented
           Product: gcc
           Version: 7.0.1
            Status: UNCONFIRMED
          Severity: normal
          Priority: P3
         Component: c
          Assignee: unassigned at gcc dot gnu.org
          Reporter: andres at anarazel dot de
                CC: dmalcolm at gcc dot gnu.org
  Target Milestone: ---

Created attachment 40989
  --> https://gcc.gnu.org/bugzilla/attachment.cgi?id=40989&action=edit
reproducer

Hi,

-Wmisleading-indentation doesn't trigger when the misindented part of the code
consists of a macro.  The attached example is silent when a macro is used, and
warns when a function is used.

#ifdef TRIGGER
static void elog(char *msg) { }
#else
#define elog(Y) printf(Y)
#endif

void foo (void);

void test (int flag)
{
  if (flag)
    foo ();
    elog("could not identify CTID variable");
}


andres@alap4:~$ gcc -DTRIGGER -Wmisleading-indentation -c /tmp/repro.c 
/tmp/repro.c: In function 'test':
/tmp/repro.c:13:3: warning: this 'if' clause does not guard...
[-Wmisleading-indentation]
   if (flag)
   ^~
/tmp/repro.c:15:5: note: ...this statement, but the latter is misleadingly
indented as if it were guarded by the 'if'
     elog("could not identify CTID variable");
     ^~~~

andres@alap4:~$ gcc -Wmisleading-indentation -c /tmp/repro.c 
andres@alap4:~$ gcc --version
gcc (Debian 20170226-1) 7.0.1 20170226 (experimental) [trunk revision 245744]
Copyright (C) 2017 Free Software Foundation, Inc.
This is free software; see the source for copying conditions.  There is NO
warranty; not even for MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.


Not sure if this is a known "issue", or not.  If it's hard to make that work
reliably for macros...

Andres