[Bug c/71963] New: Showing incompatible type when types are same.

["sinu.nayak2001 at gmail dot com" <gcc-bugzilla at gcc dot gnu dot org>]

https://gcc.gnu.org/bugzilla/show_bug.cgi?id=71963

            Bug ID: 71963
           Summary: Showing incompatible type when types are same.
           Product: gcc
           Version: 4.6.2
            Status: UNCONFIRMED
          Severity: normal
          Priority: P3
         Component: c
          Assignee: unassigned at gcc dot gnu.org
          Reporter: sinu.nayak2001 at gmail dot com
  Target Milestone: ---

#include <stdio.h>
int main()
{
        int k[3][3] = {{1,2,3},{4,5,6},{7,8,9}};
        int (*c)[3];
        int (*d)[3];
        c = k+1;
        d = k+2;
        *c = *d; //error: incompatible types when assigning to type 'int[3]'
from type 'int *'
        k[0] = k[1]; //error: incompatible types when assigning to type
'int[3]' from type 'int *'
        printf("%d\n", (*c)[0]);
        printf("%d\n", (*d)[0]);

        return 0;
}


In the above code, errors are shown as commented.
No doubt, it is a tricky attempt to assign an array to another array.
However, aren't the types of both left hand side and right hand side same?


Sincerely,
Srinivas Nayak