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[Bug sanitizer/63806] #UBSAN ignores signed char possible overflow
- From: "jakub at gcc dot gnu.org" <gcc-bugzilla at gcc dot gnu dot org>
- To: gcc-bugs at gcc dot gnu dot org
- Date: Mon, 10 Nov 2014 13:24:42 +0000
- Subject: [Bug sanitizer/63806] #UBSAN ignores signed char possible overflow
- Auto-submitted: auto-generated
- References: <bug-63806-4 at http dot gcc dot gnu dot org/bugzilla/>
https://gcc.gnu.org/bugzilla/show_bug.cgi?id=63806
Jakub Jelinek <jakub at gcc dot gnu.org> changed:
What |Removed |Added
----------------------------------------------------------------------------
Status|UNCONFIRMED |RESOLVED
Resolution|--- |INVALID
--- Comment #1 from Jakub Jelinek <jakub at gcc dot gnu.org> ---
? That is the correct thing to do, there is no undefined behavior in C/C++ in
that testcase, for any a/b values.
a + b in C is computed on promoted arguments, so (signed char) ((int) a + (int)
b) in this case, so as long as signed char is narrower than int, it is fine.