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[Bug c++/61259] New: Spurious "ISO C++ forbids zero-size array" warning with -pedantic
- From: "bugs at qult dot net" <gcc-bugzilla at gcc dot gnu dot org>
- To: gcc-bugs at gcc dot gnu dot org
- Date: Tue, 20 May 2014 18:40:54 +0000
- Subject: [Bug c++/61259] New: Spurious "ISO C++ forbids zero-size array" warning with -pedantic
- Auto-submitted: auto-generated
https://gcc.gnu.org/bugzilla/show_bug.cgi?id=61259
Bug ID: 61259
Summary: Spurious "ISO C++ forbids zero-size array" warning
with -pedantic
Product: gcc
Version: 4.8.2
Status: UNCONFIRMED
Severity: minor
Priority: P3
Component: c++
Assignee: unassigned at gcc dot gnu.org
Reporter: bugs at qult dot net
The following code, when compiled with -pedantic, compiles properly but
produces a warning about zero-sized array 'argv'.
#include <iostream>
struct Foo {
Foo(const char* s) : p(s) {}
const char* p;
};
int main(int, char* argv[])
{
const char* s(Foo(argv[0]).p);
std::cout << s << std::endl;
return 0;
}
I understand that const char* s(Foo(argv[0])) is to be understood as being a
declaration of function s taking an array of 0 Foo and returning a const char*,
but with the '.p', apparently the compiler resolves the ambiguity by itself and
the code does build an instance of Foo with argv[0] as an argument.
So in any case, something's wrong: either this code should not compile or it
should not issue the warning.