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[Bug c++/52763] Warning if compare between enum and non-enum type
- From: "gccreports at gmx-topmail dot de" <gcc-bugzilla at gcc dot gnu dot org>
- To: gcc-bugs at gcc dot gnu dot org
- Date: Wed, 04 Apr 2012 14:22:45 +0000
- Subject: [Bug c++/52763] Warning if compare between enum and non-enum type
- Auto-submitted: auto-generated
- References: <bug-52763-4@http.gcc.gnu.org/bugzilla/>
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=52763
--- Comment #3 from Mikka <gccreports@gmx-topmail.de> 2012-04-04 14:22:45 UTC ---
(In reply to comment #2)
> But what about cases such as (val1 == (ONE|TWO)) ?
>
> (ONE|TWO) is of type 'int' but that code is correct and shouldn't warn
In my opinion, there should be a warning here, because (ONE|TWO) is not in the
enumeration range (there is no definition for 3).
If it was defined (e.g. typedef enum {NONE = 0, ONE = 1, TWO = 2, THREE = 3}
tEnumType), result could again be of the enumeration type and there would be no
warning.