[Bug fortran/35036] illegal E format descriptor produces wrong output

["furue at hawaii dot edu" <gcc-bugzilla at gcc dot gnu dot org>]

------- Comment #5 from furue at hawaii dot edu  2008-01-31 02:45 -------
Subject: Re:  illegal E format descriptor produces wrong
 output

| There is no restriction in F95 that d must be positive in Ew.d.
| In 10.6.5.1, it clearly states that k = 0 at the beginning of 
| execution of an input/output statement.  The wording you quote
| above is (almost) identical to F95 language, so one could argue
| that the -d < k <= 0 is true when d = 0 and k = 0.

I may be missing something, but "-d < k <= 0" doesn't hold
when d = 0 and k = 0.  Notice the inequality "<".  So, when k = 0,
how should we read the part we quote?

| In any event, gfortran is definitely giving a bogus answer
| of 0E+1, and your desired output of ******* is probably the
| right thing to do.

I like that.  But, for the sake of curiosity, how does the Fortran
standard describe the process that leads to *******?  I mean, suppose
E8.0 is legal, but still can we emit *******?

Ryo


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http://gcc.gnu.org/bugzilla/show_bug.cgi?id=35036