[Bug c++/29164] Overloaded operator delete[] doesn't get called

["fang at csl dot cornell dot edu" <gcc-bugzilla at gcc dot gnu dot org>]

------- Comment #6 from fang at csl dot cornell dot edu  2007-03-08 22:58 -------
Subject: Re:  Overloaded operator delete[] doesn't get called

This following test case is 'interesting':

---------------->8 snip 8<---------------------
#include <iostream>
using std::cout;

class one_array_only {
private:
        static one_array_only                           pool[256];
public:

static void * operator new[] (std::size_t size) throw() {
        cout << "class new[] operator\n";
#if WTF
        return pool;
#else
        return NULL;
#endif
}

static void operator delete[] (void *p) throw() {
        cout << "class delete[] operator\n";
}
};

one_array_only
one_array_only::pool[256];

int
main(int argc, char* argv[]) {
        one_array_only* p = new one_array_only[12];
        delete [] p;
        return 0;
}

---------------->8 snip 8<---------------------

Above, in operator new[], If WTF is false, returning NULL, I reproduce the
same error (missing call to class operator delete []).  If WTF is true
(returning pool), the right operator delete [] is called.

// output with WTF false
class new[] operator

// output with WTF true
class new[] operator
class delete[] operator

Tested on: powerpc-apple-darwin8-g++-4.0.1

Why on earth would the definition inside operator new[] influence whether
or not operator delete[] is called?


Fang


-- 


http://gcc.gnu.org/bugzilla/show_bug.cgi?id=29164