[Bug c++/30657] New: template class derived from template class does not access base class' members

["paolo dot greppi at tiscali dot it" <gcc-bugzilla at gcc dot gnu dot org>]

Listing 1 compiles fine:
class smallclass {
public:
  int uu;
  smallclass(void) : uu(1) { }
};

class largeclass : public smallclass {
public:
  int *uup;
  void test(void) { uup = &(smallclass::uu); }
};

int main () {
  largeclass a;
  a.test();
}

Listing 2 fails:
template <class E> class smallclass {
public:
  E uu;
  smallclass(void) : uu(1) { }
}; // class smallclass

template <class E> class largeclass : public smallclass<E> {
public:
  E *uup;
  void test(void) { uup = &(uu); }
};

int main () {
  largeclass<int> a;
  a.test();
}
The error on compile on both gcc-4.0.1 and 3.4.1 is:
'uu' was not declared in this scope or `uu' undeclared

If one tries to fix it like this:
  void test(void) { uup = &(smallclass<E>::uu); }
the error on both gcc-4.0.1 and 3.4.1 becomes:
error: cannot convert 'int smallclass<int>::*' to 'int*' in assignment

All code compiles fine on:
- Microsoft (R) 32-bit C/C++ Optimizing Compiler Version 14.00.50727.762 for
80x86 (Visual Studio 2005)
- cxx (v6.5 su Tru64/alpha) 
- aCC (vA.5.55 per HP-UX/Itanium)
- intel cc 9.0
- gcc 3.2 and 3.3
- Comeau C++ 4.3.3


-- 
           Summary: template class derived from template class does not
                    access base class' members
           Product: gcc
           Version: 4.0.1
            Status: UNCONFIRMED
          Severity: normal
          Priority: P3
         Component: c++
        AssignedTo: unassigned at gcc dot gnu dot org
        ReportedBy: paolo dot greppi at tiscali dot it
 GCC build triplet: i686-pc-cygwin
  GCC host triplet: i686-pc-cygwin
GCC target triplet: i686-pc-cygwin


http://gcc.gnu.org/bugzilla/show_bug.cgi?id=30657