[Bug c/25155] New: Base type of expressions involving short operands is shown as int

["santhosh dot selvaraj at wipro dot com" <gcc-bugzilla at gcc dot gnu dot org>]

I don't know whether it is a bug or not.

Consider the following example:

short int sh1 = 1;
short int sh2 = 2;

printf("Size of short: %d\n", sizeof(short));
printf("Size of int: %d\n", sizeof(int));
printf("Size of expr: %d\n", sizeof(sh1+sh2));

Output:
Size of short: 2
Size of int: 4
Size of expr: 4

GCC is converting short to int while doing any arithmatic operation. Can anyone
explain why it is happening and where exactly(function) does this conversion
happen?


-- 
           Summary: Base type of expressions involving short operands is
                    shown as int
           Product: gcc
           Version: unknown
            Status: UNCONFIRMED
          Severity: normal
          Priority: P3
         Component: c
        AssignedTo: unassigned at gcc dot gnu dot org
        ReportedBy: santhosh dot selvaraj at wipro dot com


http://gcc.gnu.org/bugzilla/show_bug.cgi?id=25155