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[Bug fortran/18108] [gfortran] overloading does not work for functions
- From: "tobi at gcc dot gnu dot org" <gcc-bugzilla at gcc dot gnu dot org>
- To: gcc-bugs at gcc dot gnu dot org
- Date: 30 Nov 2004 15:21:44 -0000
- Subject: [Bug fortran/18108] [gfortran] overloading does not work for functions
- References: <20041022084631.18108.martin@mpa-garching.mpg.de>
- Reply-to: gcc-bugzilla at gcc dot gnu dot org
------- Additional Comments From tobi at gcc dot gnu dot org 2004-11-30 15:21 -------
(In reply to comment #2)
> Surprisingly (to me), adding a second call to the function resolves the problem,
> i.e. in the examples below the following code works
>
> subroutine baz
> logical l
> l = bar (3)
> l = bar (3) ! alternatively, call l=bar(3.0)
> end subroutine
>
I verified that it actually calls the right routine under these circumstances.
>From the compiler output with -fump-parse-tree:
ASSIGN l bar_real[[((3.0000000))]]
ASSIGN l bar_real[[((3.0000000))]]
Weird.
> Commenting out either of the calls to bar results in the code rejection
--
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=18108