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[Bug c++/11893] New: stdcall pointers to member-functions handled wrong


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http://gcc.gnu.org/bugzilla/show_bug.cgi?id=11893

           Summary: stdcall pointers to member-functions handled wrong
           Product: gcc
           Version: 3.2.2
            Status: UNCONFIRMED
          Severity: critical
          Priority: P2
         Component: c++
        AssignedTo: unassigned at gcc dot gnu dot org
        ReportedBy: boaz at hishome dot net
                CC: gcc-bugs at gcc dot gnu dot org
GCC target triplet: i386-pc-linux

the compiler will not let me declare an __stdcall__ pointer to function member
and code will than SEGFAULT on invocation of the member pointer.  This is not
the case for Regular pointers to functions. ( The compiler will also issue a
warning  on mismatch.)

Listing of the Error: (BAD)

class AFoo
{
public:
    __attribute__((__stdcall__))
    void foo(int i ,int ii ,int iii) ;
} ;

__attribute__((__stdcall__))
void AFoo::foo(int i ,int ii ,int iii)
{
    return ;
}

int main()
{
  AFoo afoo ;
  void ( AFoo::*func)(int,int,int) ;
  func = &AFoo::foo ;

  for(int i=0 ; i < 0x8000000 ;i++)
     (afoo.*func)(1,2,3) ; // SEGFAULT or SEGIL when stack is Exhausted
  return 0 ;
}

any attempt  to place the __atribute__((stdcall)) in the pointer declaration
causes a compilation error. With out it the code will SEGFAULT.

If declaring a regular pointer to function than no compilation error is issued 
and all is well.

Listing of Regular function pointer: (GOOD)

void __attribute__((stdcall)) foo(int i ,int ii ,int iii)
{
}

int main()
{
  void ( __attribute__((stdcall)) *func)(int,int,int) = &foo ;

  for(int i=0 ; i < 0x8000000 ;i++)
     (func)(1,2,3) ;

  return 0 ;
}

removing the __attribute__((stdcall)) from the *func declaration will rightfully
issue a warning ( should be an error if you ask me, type mismatch).
But Not so on our first example.


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