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Why is there a `0' flag used with `%I' in asm_fprintf ?
- From: "Kaveh R. Ghazi" <ghazi at caip dot rutgers dot edu>
- To: gcc-bugs at gcc dot gnu dot org, gcc at gcc dot gnu dot org
- Date: Thu, 22 May 2003 10:17:47 -0400 (EDT)
- Subject: Why is there a `0' flag used with `%I' in asm_fprintf ?
Many uses of asm_fprintf in m68k.c and a few in m68hc11.c use the `0'
flag in conjunction with `%I' when calling asm_fprintf. Reading
through the function body of asm_fprintf in final.c, it appears that
the zero is consumed, but has no effect. I.e. `%0I' just spits out
IMMEDIATE_PREFIX unmodified as would plain `%I'.
So it seems harmless except for the fact that someone reading the code
in m68k.c might think the `0' flag is supposed to do something.
Should all instances of `%0I' be changed to `%I', or have I missed
something?
Thanks,
--Kaveh
--
Kaveh R. Ghazi ghazi@caip.rutgers.edu