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c++/9447: using Base<T>::member does not work
- From: rguenth at tat dot physik dot uni-tuebingen dot de
- To: gcc-gnats at gcc dot gnu dot org
- Date: 27 Jan 2003 08:50:41 -0000
- Subject: c++/9447: using Base<T>::member does not work
- Reply-to: rguenth at tat dot physik dot uni-tuebingen dot de
>Number: 9447
>Category: c++
>Synopsis: using Base<T>::member does not work
>Confidential: no
>Severity: critical
>Priority: medium
>Responsible: unassigned
>State: open
>Class: rejects-legal
>Submitter-Id: net
>Arrival-Date: Mon Jan 27 08:56:00 UTC 2003
>Closed-Date:
>Last-Modified:
>Originator: Richard Guenther
>Release: [3.4 regression] g++-3.4 (GCC) 3.4 20030124 (experimental)
>Organization:
>Environment:
ix86-linux
>Description:
In the following testcase, member i of Foo is not brought to scope by the using declaration, instead g++ reports:
bellatrix:~/src/tests$ g++-3.4 -c using3.cpp -Wall
using3.cpp: In member function `void Bar<T>::foo()':
using3.cpp:11: error: `i' has not been declared
this works with both 3.2 and 3.3 (in fact, they dont care if I omit the using declaration, too, but in whole this is a regression).
template <class T>
struct Foo {
int i;
};
template <class T>
struct Bar : public Foo<T> {
using Foo<T>::i;
void foo()
{
i = 0;
}
};
int main()
{
Bar<int> bar;
bar.foo();
return 0;
}
>How-To-Repeat:
>Fix:
>Release-Note:
>Audit-Trail:
>Unformatted: