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c++/8680: g++ doesn't warn when passing a C++ funcptr instead of extern "C" funcptr
- From: apm35 at student dot open dot ac dot uk
- To: gcc-gnats at gcc dot gnu dot org
- Date: 22 Nov 2002 17:15:24 -0000
- Subject: c++/8680: g++ doesn't warn when passing a C++ funcptr instead of extern "C" funcptr
- Reply-to: apm35 at student dot open dot ac dot uk
>Number: 8680
>Category: c++
>Synopsis: g++ doesn't warn when passing a C++ funcptr instead of extern "C" funcptr
>Confidential: no
>Severity: non-critical
>Priority: low
>Responsible: unassigned
>State: open
>Class: sw-bug
>Submitter-Id: net
>Arrival-Date: Fri Nov 22 09:16:02 PST 2002
>Closed-Date:
>Last-Modified:
>Originator: Andrew Marlow
>Release: unknown-1.0
>Organization:
>Environment:
Solaris 8, GCC version 3.2
>Description:
extern "C" is now part of functions type in C++. This means that function type matching must take this into account. The attached program has an extern "C" function that takes a function pointer parameter. This should also be treated as a function with extern "C" (see the standard, section 7.5 clause 4) so when a function pointer is passed the compiler should check that it has extern "C" linkage. If it doesn't then at least a warning should be issued. The Solaris Forte 6.2 compiler DOES issue such a warning.
>How-To-Repeat:
Compile the attached file, g++ -c -Wall -pedantic bug.cpp
>Fix:
>Release-Note:
>Audit-Trail:
>Unformatted:
----gnatsweb-attachment----
Content-Type: text/plain; name="bug.cpp"
Content-Disposition: inline; filename="bug.cpp"
extern "C" {
void doSomething(int, void*(*)(void*));
};
void* func(void*);
int main()
{
doSomething(1, func);
return 0;
}