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Re: throw ()


On Aug 30, 2000, Mike Harrold <mharrold@cas.org> wrote:

> void foo() throw ();

> indicates that foo() throws no exceptions.

It actually indicates that, if any exceptions are thrown, the function
unexpected() will be called, instead of having it propagated out by
stack unwinding.

> If that is the case, shouldn't the compiler warn about:

> void foo() throw ()
> {
>   throw "Oops!";
> }

I think warning in this case would be a good idea.

-- 
Alexandre Oliva   Enjoy Guarana', see http://www.ic.unicamp.br/~oliva/
Red Hat GCC Developer                  aoliva@{cygnus.com, redhat.com}
CS PhD student at IC-Unicamp        oliva@{lsd.ic.unicamp.br, gnu.org}
Free Software Evangelist    *Please* write to mailing lists, not to me


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