Re: int a[0]={2};

[Kip Macy <kip at lyris dot com>]

Looking at the assembly for it, it is pretty obvious what is wrong:
 more test.s 
        .file   "test.c"
gcc2_compiled.:
.section        .rodata
.LC0:
        .string "%i\n"
.text
        .align 4
.globl main
        .type    main,@function
main:
        pushl %ebp
        movl %esp,%ebp
        subl $24,%esp
        movl $5,-4(%ebp)
        movl $2,-4(%ebp) # here it moves 2 into memory where 5 already is
        addl $-8,%esp
        movl -4(%ebp),%eax
        pushl %eax
        pushl $.LC0
        call printf
        addl $16,%esp
.L2:
        leave
        ret
.Lfe1:
        .size    main,.Lfe1-main
        .ident  "GCC: (GNU) 2.95 19990728 (release)"



Why it does this is  a question for the code-generation guys.

					-Kip


On Wed, 18 Aug 1999, Klaus Niederkrueger wrote:

> Hi,
> 
> I think I have found a small bug: Try this program on Linux
> 
> 	egcs-2.91.60 Debian 2.1 (egcs-1.1.1 release)
> 
> or
> 
> 	gcc version 2.7.2.3
> .
> ------------------
> 
> 
> int main()
> {
>   int b= 5;
>   int a[0]={2};
> 
>   printf("%i\n",b);
> }
> 
> ----------------------
> 
> 
> On my machine the computer gives "2" as result instead of "5" and even if I 
> switch on "-Wall" I get no warning.
> 
> If I use the following program
> 
> --------------------
> 
> 
> int main()
> {
>   int b= 5;
>   int a[1]={2, 2};
> 
>   printf("%i\n",b);
> }
> 
> ----------------------
> 
> I get the warning message at compile-time 
> 
> test.c:4: warning: excess elements in array initializer after `a'
> 
> and the result is "5" as it should be...
> 
> 
> 
> I hope I am right and I don't waste your time.
> 
> Greetings 
> 
> 	Klaus
> 
> 
> 
> 
> 
>