The call of a constexpr member of a class into a static member of the same class is not working. This is illustrated by the following code:
(tested on g++ 4.7.1 and 4.7.2, but it may also affect g++ 4.8)

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#include <iostream>
#include <type_traits>

template<typename Type>
class Test
{
    public:
        constexpr Test(const Type val) : _value(val) {}
        constexpr Type get() const {return _value;}
        static void test()
        {
            static constexpr Test<int> x(42);
            std::integral_constant<int, x.get()> i; // This is not working
            std::cout<<i<<std::endl;
        }
    protected:
        Type _value;
};

int main(int argc, char *argv[])
{
    static constexpr Test<int> x(42);
    std::integral_constant<int, x.get()> i; // This is working
    std::cout<<i<<std::endl;
    Test<double>::test();
    return 0;
}
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which produces the following error:

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main.cpp: In static member function ‘static void Test<Type>::test()’:
main.cpp:13:48: erreur: invalid use of ‘Test<Type>::get<int>’ to form a pointer-to-member-function
main.cpp:13:48: note:   a qualified-id is required
main.cpp:13:48: erreur: could not convert template argument ‘x.Test<Type>::get<int>()’ to ‘int’
main.cpp:13:51: erreur: invalid type in declaration before ‘;’ token
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